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| 24 August 2021 : Shift 2 (English) |
Question. 1.
Download Our AppAvinash has 20% less coins of different countries than Gaurav has. Gaurav has 40% more such coins than Chetan has. By what percent the number of coins which Chetan has is less than the number of coins which Avinash has? (correct to one decimal place)
Answer (Detailed Solution & Explanation Below)
Option 4 : 10.7
Solution & Explanation
Subscribe Our You Tube ChannelGiven:
Avinash has 20% less coins of different countries than Gaurav has.
Gaurav has 40% more such coins than Chetan has.
Concept used:
Application of percentage
Calculation:
Let Chetan has 100P coins.
So, the number of coins Gaurav has = 100P + (100P × 40%) = 140P
So, the number of coins Avinash has = 140P - (140P × 20%) = 112P
Now, the number of coins Chetan less has than Anivash = (112P - 100P) = 12P
Then,
the percentage = (12P/112P) × 100% ≈ 10.7%
∴ By 10.7% the number of coins that Chetan has is less than the number of coins that Avinash has.
Answer (Detailed Solution & Explanation Below)
Option 3 : 20
Solution & Explanation
Subscribe Our You Tube ChannelGiven
x - 2/x = 4
Formula used
(a - b)2 = a2 + b2 - 2ab
Calculation:
x - 2/x = 4
Squaring both side
⇒ x2 + 4/x2 - 4 = 16
⇒ x2 + 4/x2 = 20
∴ The required answer is 20.
Answer (Detailed Solution & Explanation Below)
Option 1 : 17/2
Solution & Explanation
Subscribe Our You Tube ChannelCalculation:
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